What are the solutions to the equation 3(x-4)^2=27

Answer:x=1, x=7Step-by-step explanation:Firstly, you can simplify by dividing both sides by 3, which will make the equation easier to simplify:(x-4)^2=9Next, you can take the square root of each side, which will cancel the square, and make the 9 even easier to work with:(x-4)=(± )3*Note the (± ) sign, this is because there is a positive and negative answer*After this, you will basically have two equations:(x-4)=3and(x-4)=-3You are going to solve both to get both answers, but lets start with the positive first: x-4=3     Add 4 to both sides to get an x= equation x=7And it's the same thing for the negative:x-4=-3     Add 4 to both sides to get an x= equation x=1Hope this helps