MATH SOLVE

4 months ago

Q:
# PLEASE HELP WILL GIVE BRAINLIEST!!!!! A survey asked students whether they have any siblings and pets.

Accepted Solution

A:

Answer:Option B.Step-by-step explanation:The given table represents the relative frequency.Let A and B represent the following events.A : Student does not have a siblingB : Students has a pet.Then intersection of A and B (A∩B) denotes the event that the student does not have a sibling but has a pet.Using the given table it is clear that P(A∩B) = 0.15We need to find the probability that the student does not have a pet given that student has a sibling. It means we need to find the value of P(B|A).Formula for conditional probability:[tex]P(B|A)=\dfrac{P(A\cap B)}{P(A)}[/tex]Substitute the given values.[tex]P(B|A)=\dfrac{0.15}{0.25}[/tex][tex]P(B|A)=\dfrac{3}{5}[/tex][tex]P(B|A)=0.6=60\%[/tex]The probability that the student does not have a pet given that student has a sibling is 60%.Therefore, the correct option is B.